-4.9x^2+26x+0.25=0

Solution for -4.9x^2+26x+0.25=0 equation:

-4.9x^2+26x+0.25=0

a = -4.9; b = 26; c = +0.25;
Δ = b2-4ac
Δ = 262-4·(-4.9)·0.25
Δ = 680.9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-\sqrt{680.9}}{2*-4.9}=\frac{-26-\sqrt{680.9}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+\sqrt{680.9}}{2*-4.9}=\frac{-26+\sqrt{680.9}}{-9.8}
$